Test note
2026-02-24 15:36 UTC
Hello, world!
This is just a test.
Euler's identity is \(e^{i\pi}+1=0\), while the Fourier transform formula is
\[ \hat{f} (\xi)=\int_{-\infty}^{\infty}f(x)e^{-2\pi ix\xi}dx \]
Here follows a beautiful plot.
2026-02-24 15:36 UTC
Hello, world!
This is just a test.
Euler's identity is \(e^{i\pi}+1=0\), while the Fourier transform formula is
\[ \hat{f} (\xi)=\int_{-\infty}^{\infty}f(x)e^{-2\pi ix\xi}dx \]
Here follows a beautiful plot.